When rolled down a mountainside at 7.0 m/s, the horizontal component of its velocity vector was 1.8 m/s. What was the angle of the mountain surface above the horizontal? A) 75° B) 15° C) 33° D) 57° E) 37°
Added by Deanna C.
Close
Step 1
Step 1: The horizontal component of the velocity vector is given by \(V_x = V \cdot \cos(\theta)\), where \(V\) is the magnitude of the velocity and \(\theta\) is the angle of the mountain surface above the horizontal. Show more…
Show all steps
Your feedback will help us improve your experience
Prabhu Ramji and 71 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
When Jeff ran up a hill at 6.2 m/s, the horizontal component of his velocity vector was 5.5 m/s. What was the vertical component of Jeff's velocity?
James K.
When Jeff ran up a hill at 6.8 m/s, the horizontal component of his velocity vector was 4.8 m/s. What was the vertical component of Jeff's velocity?
Hubert A.
SSM An airplane with a speed of 97.5 m/s is climbing upward at an angle of 50.0 with respect to the horizontal. When the plane’s altitude is 732 m, the pilot releases a package. (a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth. (b) Relative to the ground, determine the angle of the velocity vector of the package just before impact.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD