00:03
We are asked to write a balanced chemical equation for the reaction between lead sulfide and oxygen gas.
00:14
Okay, we're told that the products are solid lead oxide and so2 gas.
00:20
Very good.
00:21
So i am going to need a two here, a two here and a two here and probably a three here.
00:29
Let me verify this.
00:30
Two leads, two leds, two sulfers, two sulfers, six oxygens and two four six.
00:35
There's my balance chemical equation.
00:37
That's a.
00:51
B says given or where else to find mass in grams of o2, to react with 29 .9 grams of lead sulfide.
01:24
Okay.
01:35
So i will need the molar mass of pbs.
01:40
Sounds like a radio station or a tv station.
01:44
That's 239 .3.
01:59
Then i will convert that to moles of oxygen using our mole ratio from our balanced chemical equation.
02:11
Finally, i'll multiply that by 32 grams of 02 per mole of 02.
02:18
29 .9 times 3 times 32 divided by 239 .3 divided by 2 .3 divided by 2.
02:28
Whoops, i got a bad number there.
02:30
239 .3 divided by 2.
02:36
Delete that number and i get 5 .9975 grams to 3 figs i will have 6 .00 grams of 02.
02:52
There's b.
02:57
How many grams of s -o2? let's go see from 65 .0 grams of pbs.
03:42
This will be a 2 to 2 mole ratio.
03:53
And i believe this will be right around 64 grams per mole...