00:01
Hi, in this question we are given by the e -cell of the reaction and ag plus concentration is 1 .04 molar.
00:09
And we have to find the concentration of magnesium ion in the given equation.
00:16
And e -0 value of magnesium 2 plus 2mg is minus 2 .36 volt and e -0 for ag plus 2a -g is plus 0 .80 volt.
00:26
So now we have to apply the ners equation.
00:30
So the nursed equation is e -cell is equals to e0 cell minus 0 .091 divided by n log concentration of product which is mg 2 plus divided by concentration of reactant which is ag plus and it's tociomatase 2 so it goes to the power and magnesium in the form of solid and a in the form of solid are not considered in the concentration because the concentration of solid remain constant.
01:07
So now we have to put the values in the formula.
01:11
So e -cell is 3 .262 volt equals to e0 cell is equal to the reduction of the reduced species minus reduction potential of the oxidized species.
01:26
So in this reaction, ag plus is getting reduced and mg is getting reduced.
01:30
Oxidize.
01:31
So, e0 cell will be equals to 0 .80 minus 2 .36 volt minus 0 .0 .0591 divided by number of electrons involve in this reaction are 2 because magnesium is converting from 0 to plus 2 states.
01:51
So there are 2 electron change and ag plus is converting into ag.
01:56
So there is 1 electron change and we have 2 ag plus so the number of electron will be 2.
02:05
Then logarithm magnesium 2 plus ion concentration we have to identify this divided by ag plus concentration is 1 .04 and it's square...