00:01
We can say that theta is equaling 45 degrees.
00:02
This would give us the maximum range.
00:05
And we can then say that here, the range is equaling v initial square times sine of 2 theta divided by g.
00:14
And so sign of 2 theta becomes 1.
00:17
2 times theta is 90 degrees.
00:18
Sign of 90 degrees is 1.
00:20
And so we can then say that here, to solve for v initial, this would be equal to square root of rg.
00:30
And so this is the initial equaling the square root of the range, which we know to be 60 meters, multiplied by 9 .8 meters per second squared.
00:43
And we have the initial equaling 24 .25 meters per second.
00:52
This would be our initial velocity without any wind.
00:56
Now here for part b, we do have wind...