00:01
Hello everyone, let's see the question.
00:02
According to the question in part a, we are having n1 is equals to 3 .60 and 2 is equals to 3 .30.
00:15
Now r parallel is equals to r er is equals to n1 minus n2 divided n1 plus n2.
00:30
Then it is equals to 3 .60 minus 3 .30 divided 3 .60 plus 3 .30.
00:41
On solving this we get it equals to 0 .043.
00:46
Now r is equals to r perpendicular is equals to r parallel square.
01:03
So it is the transmittance is t parallel is equals to 2n1 plus n1 plus n2 is equals to 2 multiply 3 .60 divided 3 .60 plus 3 .30 is equals to 1 .043 and the t perpendicular is equals to t parallel is equals to the 4n1 n2 divided n1 plus n2.
01:48
Then it is equals to 4 multiply 3 .60 multiply 3 .30 divided 3 .60 plus 3 .30.
01:57
On solving this we get it equals to 0 .998.
02:02
Now as to be moving further to part b of this question, then according to the part b, we get the theta p is equals to tan inverse n2 divided n1.
02:20
Then it is equals to tan inverse 3 .3 divided 3 .6 which is equals to 42 .51 degree.
02:31
Now the critical angle theta c is equals to sine inverse n2 divided n1 is equals to sine inverse 0 .0917 is equals to 66 .49 degree...