When the light passes through the glass block, it is shifted laterally by the distance d. Find the time interval required for the light to pass through the glass block, where t = 2.05 cm, n = 1.50, and θ = 29.5°. Why is the answer 109 ps?
Added by David L.
Step 1
5 (refractive index of glass), θ1 = 29.5° Using Snell's Law: n1*sin(θ1) = n2*sin(θ2) 1*sin(29.5°) = 1.5*sin(θ2) sin(θ2) = (1*sin(29.5°))/1.5 sin(θ2) = 0.316 θ2 = sin^(-1)(0.316) θ2 ≈ 19.6° Show more…
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