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Hello students.
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In this question we are given electronic configuration of zirconium.
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Electronic configuration of zirconium is given as electronic configuration of krypton, 4d2 and 5h2.
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So we need to tell that if it will lose an electron then which will be the first cell from where the electron will be lost and how many different types of ions it can form.
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So if we draw its configuration of outer cell, it is something like this and 5s over here.
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Let's make it small and this is also 5.
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1, 2, 3, 4, 5 and this will be s.
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So this is 4d and this is 5s.
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So the electrons are filled like this.
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D has two electrons and s has two electrons...