00:01
Hello students in the question we are given that a ball is being lifted and we have to find acceleration of the ball.
00:09
From the free body diagram we can write applied force f minus weight of ball m g it is equal to mass times acceleration.
00:21
Here m it is mass of ball.
00:23
G denotes acceleration due to gravity and a it is net acceleration.
00:28
Here g, it has value 9 .8 meter per second square.
00:36
We have f1 equal to 66 .2 newton.
00:41
If corresponding to this, we have a1 equal to a, f2 equal to 72 .7 newton, and a2 equal to 1 .95a.
00:55
Putting in these values, in the equation, we can write 66 .2 minus m g it is equal to ma or we can write 66 .2 it is equal to mass times a plus g.
01:12
This is equation number one.
01:15
For second force we can write 72 .7 minus m g it is equal to mass times acceleration that is 1 .95a or we get 72 .7 .2 .7 .m.
01:30
It is equal to mass times 1 .95a plus g this is equation number two we can divide first equation by second equation and we get 66 .2 divided by 72 .7 it is equal to m a plus g divided by m here we can cancel m.
02:06
Here g it is equal to 9 .8 meter per second square.
02:12
Substituting its value, we can write 66 .2 divided by 72 .7, it is equal to a plus 9 .8 divided by 1 .95a plus 9 .a.
02:29
Then we can write 66 .2 into 1 .95a plus 66 .2 into 9 .8 it is equal to 72 .7 a plus 72 .7 into 9 .8...