00:01
So, in this question, for the open -closed tube, for the frequency of fm is given by m, v by 4l, where m is equal to 135 dash dash dash, v is the speed of sound and l is the length of the tube.
00:17
Now, it is also given that sound is to be taken as, that is v has to be taken as 350 meter per second and the frequency of the wave of the throat, that is ft is given as 800 hertz and the frequency of the wave in the mouth, that is fm is given as 1500 hertz.
00:41
This is the given data in the question.
00:45
Now, the length of the tube in the throat, that is lt will be equal to, we will put m is equal to 1 and f is equal to ft.
00:53
This is equation 1, in equation we will put, so this will become v by 4ft, which will be equal to 3500 divided by 4 into 800 m, this will be equal to 0 .11 m.
01:09
So, this is the length of the tube in the throat...