Question

Example 9-4 Calculate using a simple rule of mixture model the percentage of load borne by mineral phase of a cow femur that is subjected to 500 N of load. Assume that the Young's modulus of mineral and collagen is about 17 and 0.1 GPa, respectively. Answer Since the area is proportional to the volume percentage of each component, from Example 9-2 and Eq. (9-6): $P_m = \frac{P_t A_m E_m}{A_m E_m + A_c E_c} \implies \frac{P_m}{P_t} = \frac{0.44(17)}{0.44(17) + 0.40(0.1)} = 0.9947$ young modulus $\implies E_m, E_c$ F=ma $\frac{F}{m} = $ $\frac{P}{A} \approx ?$ $\frac{F}{A}$

          Example 9-4
Calculate using a simple rule of mixture model the percentage of load borne by mineral phase of a
cow femur that is subjected to 500 N of load. Assume that the Young's modulus of mineral and
collagen is about 17 and 0.1 GPa, respectively.
Answer
Since the area is proportional to the volume percentage of each component, from Example 9-2 and
Eq. (9-6):
$P_m = \frac{P_t A_m E_m}{A_m E_m + A_c E_c} \implies \frac{P_m}{P_t} = \frac{0.44(17)}{0.44(17) + 0.40(0.1)} = 0.9947$
young modulus $\implies E_m, E_c$
F=ma
$\frac{F}{m} = $ 
$\frac{P}{A} \approx ?$
$\frac{F}{A}$

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Example 9-4
Calculate using a simple rule of mixture model the percentage of load borne by mineral phase of a
cow femur that is subjected to 500 N of load. Assume that the Young's modulus of mineral and
collagen is about 17 and 0.1 GPa, respectively.
Answer
Since the area is proportional to the volume percentage of each component, from Example 9-2 and
Eq. (9-6):
Pm = (Pt Am Em)/(Am Em + Ac Ec)(Pm)/(Pt) = (0.44(17))/(0.44(17) + 0.40(0.1)) = 0.9947
young modulus Em, Ec
F=ma
(F)/(m) =
(P)/(A)≈ ?
(F)/(A)

Added by Christopher L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

Step 1

Am = 17 (given) Em = 0.1 GPa = 0.1 * 10^9 Pa (since 1 GPa = 10^9 Pa) AmEm = 17 * 0.1 * 10^9 = 1.7 * 10^9 Show more…

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Example 9-4: Calculation of Load Borne by Mineral Phase in a Cow Femur Calculate, using a simple rule of mixture model, the percentage of load borne by the mineral phase of a cow femur that is subjected to a 500 N load. Assume that the Young's modulus of the mineral and collagen is approximately 17 and 0.1 GPa, respectively. Answer: Since the area is proportional to the volume percentage of each component (from Example 9-2 and Eq. 9-6), we can use the following formula: Pm = AmEm / (AmEm + AcEc) where: Pm = percentage of load borne by the mineral phase Am = area of the mineral phase Em = Young's modulus of the mineral phase Ac = area of the collagen phase Ec = Young's modulus of the collagen phase Given: P = 0.44 Am = 17 Ac = 0.40 Em = 0.1 Substituting the values into the formula, we get: Pm = 0.44(17) / (0.44(17) + 0.40(0.1))

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