Which code snippet produces the sum of the first n even numbers? Question 7 options: int sum = 0; for (int i = 1; i <= n; i++) { if (i % 2 == 0) { sum = sum + i; } } int sum = 0; for (int i = 1; i <= n; i++) { sum = sum + i * 2; } int sum = 0; for (int i = 0; i < n; i++) { if (i % 2 == 0) { sum = sum + i; } } int sum = 0; for (int i = 1; i < 2*n; i++) { sum = sum + i; }
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Choose the correct option: The function given below takes an even integer "n" as the input and calculates the sum of the first "n" even natural numbers. The function is called by the statement "sumcoy". How many times will the function "sum" be called to compute? function sum(n) if (n equals 2) return 2 return (n + sum(n-2)) end
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Choose the right answer. int X = 13; int sum = 0; while (x++ < 15) { System.out.println("x = " + x); sum += X; x++; sum += x; } System.out.println("sum = " + sum); sum = 18; sum = 20; sum = 29; none of the above.
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