00:01
In this problem, we need to analyze the electron configurations of various metal ions to understand their magnetism and, more importantly, the number of unpaired electrons we would see in their d orbitals.
00:16
For part a, we're given that we have chromium 3 plus, and when we look on the periodic table and find its electron configuration, chromium 3 plus has a 3d3 electron configuration.
00:28
And remember, we're told that these complexes are low spin cases.
00:34
So we would see that we have three unpaired electrons in this first metal ion.
00:40
And aren't to part b, we're given maganese 2 plus.
00:44
Again, we would find the electron configuration is 3d5, and when we make that crystal field splitting diagram, we would find that magonez 2 plus has one unpaired electron...