00:01
So in this question we have to consider the points p 0.
00:05
Minus 3 comma 0 and q 6 .1 comma minus 2 and our value 6 .3 comma 1 these are the given points.
00:14
So here we have to find out non -zero vector that is orthogonal to the plane which pass through the points orthogonal to plane.
00:25
So that is the question.
00:27
So here first of all by using the point value we have to.
00:31
To find out the p q ray so how to find out here so that means q minus p what is the q point 6 comma 1 minus 2 and the points p that is a my 0 comma minus 3 whenever we do that is 6 my 6 minus 0 6 minus 0 1 minus 0 6 1 minus of minus 3 then then comma minus 2 minus 0 so whenever we simplify this we'll get the value 6 comma 4 comma minus 2 this is the pq then this is the pq vector now the p q pr vector so how to find out the pr vector that is r vector that is our point values minus p point values so whenever we do this what we'll get that is 6 minus 0 0 3 minus of minus 3 1 minus 0 so whenever we do simplification we'll get 6 so this is the pr vector.
01:34
This will be the pr vector.
01:36
So here these two vectors, they are planar.
01:39
These two vectors, they are on the plane.
01:44
These two vectors they are on the plane...