Which if the following technical factor adjustments will result in a reduction in patient dose?
Added by Edwin R.
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These factors typically include: - kVp (kilovoltage peak): The higher the kVp, the higher the X-ray energy and the greater the patient dose. - mAs (milliampere-seconds): This is a measure of the X-ray tube current multiplied by the exposure time. Higher mAs values Show more…
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Constant kVp = 28 Automatic Dose Control Target: Mo Filter: Mo Focal Spot: Large Phantom: RMI model: 159 BR Phantom Thickness (cm): 3, 3.5, 4, 4.5 mAs: 46, 65, 91, 128 Dose (mR): 508, 724, 1028, 1451 Questions: The mammography unit automatically adjusts the dose to the (patient) phantom such that the exit dose is kept constant, i.e. the dose to the (film or CR) cassette is always the same. Calculate the exit dose for this unit, for kVp = 28 and Mo/Mo combination.
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Tissue wil not have an interaction other than absorbing the beam: None of the above. In laser production; increasing the density of the lasing medium will: Increase the number of photons of the produced laser beam Reduce the number of photons of the produced laser beam Has no effect at all: To decrease the unwanted biological damage for the patients during an X-ray test; we can: Decrease the applied high voltage on the X- ray tube Decrease the applied fillamnet current: Use some kind of filter to reduce the low energy X-ray to reduce the unwanted X-ray All the above None of the above.
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