00:03
Here in this problem, we have to write the iupac name of this given compound.
00:09
Now, if we start counting the number of carbon atoms in the longest chain, let's start counting from this side.
00:17
One, this is the second carbon atom, this is the third one, fourth one, fifth one, and sixth one.
00:26
So there are six carbon atoms in the longest chain of this alkin.
00:31
And here, if we start counting from this side, the third carbon atom has the methyl group, also fourth carbon atom has the methyl group.
00:42
And if we start counting from this side, we have the same situation.
00:47
Third and fourth carbon atoms contain methyl groups.
00:51
So we can write the iupac name as three, four, dye, methyl...