Since $\mathrm{Cl}_{2}$ has more electrons than $\mathrm{O}_{2}$, it will have stronger London dispersion forces and a higher boiling point.
(b) $\mathrm{SO}_{2}$ and $\mathrm{CO}_{2}$: $\mathrm{SO}_{2}$ is a polar molecule, while $\mathrm{CO}_{2}$ is nonpolar.
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