Which of the following will be the result of an attempt to compile and execute the Java SE code below? public class IkmTest { public IkmTest() { this(10); } public IkmTest(int data) { this.data = data; } public void display() { class Decrementer { public void decrement() { data--; } } Decrementer d = new Decrementer(); d.decrement(); System.out.println("data = " + data); } private int data; public static void main(String[] args) { int data = 0; IkmTest t = new IkmTest(); t.display(); System.out.println("data = " + data); } } The output will be: data = 10 data = -1 The output will be: data = 9 data = 0 The output will be: data = 0 data = 0 An error will occur. The output will be: data = 10 data = 0
Added by Michelle M.
Close
Step 1
The code has several syntax errors and typos, so it will not compile successfully. Some of the errors include: - The class declaration should be `public class IkmTest {`, but it is missing the opening curly brace `{`. - The constructor `public IkmTest () Show more…
Show all steps
Your feedback will help us improve your experience
Florencia Cuzmar and 57 other AP CS educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
What is the output of the following? class GFG { public static void main (String[] args) { int[] arr = new int[2]; arr[0] = 10; arr[1] = 20; for (int i = 0; i < arr.length; i++) System.out.println(arr[i]); } }
Madhur L.
Recommended Textbooks
Computer Science and Information Technology
Introduction to Programming Using Python
Computer Science - An Overview
Watch the video solution with this free unlock.
EMAIL
PASSWORD