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Hello, let's have a look on the question.
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Percentage of n -pentine, that is equal to 30%.
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Let's percentage of iso -optane present, that is equal to a percent, percentage of n -habtain present, that is equal to 100 -mines -30 -mine percent, that is equal to 70 -mine -a -percent, that is equal to 70.
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Minus a percent octane rating a mixture of npenteen iso obtained and an heptane that is equal to 87 a octane rating of 100 percent npenteen that is equal to 10 of 30 % of n fain that is equal to 30 into 62 divided by 100.
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Equation 1 obtained rating of 100 % iso obtained that is equal to 100.
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Octane rating of a percent iso octane that will be equal to a into 100 divided by 100, that is equation number 2.
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Octane rating of 100 % and heptain that is equal to 0...