This is true because odd numbers have the form $2n+1$ where $n$ is an integer, so $x+1 = 2n+1+1 = 2(n+1)$, which is even.
(B) The sum of two odd numbers is even. This is true because if $x$ and $y$ are odd, then $x=2n+1$ and $y=2m+1$ for some integers $n$ and
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