00:01
In this problem we have to find out the electron transitions which emits a photon with shortest wavelength.
00:13
So for emission of a photon, the electron transition must be from higher energy level to lower energy level.
00:23
So for the second, sorry, for the third transition from 2 to 3, the electron is going from lower to higher level.
00:32
So, there will be no emission of photon for this transition.
00:38
Similarly, there will be no emission of photon for the last transition from n -equal to 1 to 3.
00:45
So, we have three possible choices for which the photon can be emitted with shortest wavelength.
00:57
For the first one, the transition is 6 to 3.
01:00
So, the energy of nth level is given by minus 13 .6 upon n squared electron volt.
01:14
So for n equal to 6 to 2 and equal to 3, the energy released is delta e equal to energy of 6 level minus energy of third level.
01:31
So energy of 6 level is minus 13 .6 upon 6 square, energy of 7 .6...