00:02
Okay, so this problem is a three -parter.
00:04
First, says the nunes method is an example of a numerical method for approximating the roots of a function.
00:13
And you've probably seen a lot of the other videos in this chapter if you're watching this.
00:18
So i don't really think i need to explain it further.
00:22
So, yes, it is true.
00:26
Part b says that nunes method gives an approximation to the roots of a quadratic equation better than the quadratic formula itself does, and no, that is false.
00:36
The quadratic formula always gives an exact answer, but the nunes method is only really able to give some estimates because in the end, it's just gonna be ratios of integers.
00:54
So for example, if i were to do, let's say, x squared minus 3x plus 1, the exact one is, the exact solution is 3 plus or minus square root of all divided by 2.
01:07
So 3 minus square root of 5 over 2, for example, is an exact number and comes down to about 0 .38196601 -2501015151 -151 -179954, etc.
01:25
And if i were to run that in the newton's method calculator, it can actually only give me up to 15 decimal digits total.
01:35
So, 0 .381966011250105.
01:43
That's all that's able to give me...