Question

Which of the following is the correct order for molecules from most to least polar? a. CH4> CF2Cl2> CF2H2> CCl4> CCl2H2 b. CF2H2> CCl2H2> CF2Cl2> CH4= CCl4 c. CF2Cl2> CF2H2> CCl2H2> CH4= CCl4 d. CF2Cl2> CF2H2> CCl4> CCl2H2> CH4 e. CH4> CF2H2> CF2Cl2> CCl4> CCl2H2 

          Which of the following is the correct order for molecules from most to least polar?
a. CH4> CF2Cl2> CF2H2> CCl4> CCl2H2
b. CF2H2> CCl2H2> CF2Cl2> CH4= CCl4
c. CF2Cl2> CF2H2> CCl2H2> CH4= CCl4
d. CF2Cl2> CF2H2> CCl4> CCl2H2> CH4
e. CH4> CF2H2> CF2Cl2> CCl4> CCl2H2
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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Which of the following is the correct order for molecules from most to least polar? a. CH4> CF2Cl2> CF2H2> CCl4> CCl2H2 b. CF2H2> CCl2H2> CF2Cl2> CH4= CCl4 c. CF2Cl2> CF2H2> CCl2H2> CH4= CCl4 d. CF2Cl2> CF2H2> CCl4> CCl2H2> CH4 e. CH4> CF2H2> CF2Cl2> CCl4> CCl2H2
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Transcript

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00:01 First, we recognize that fluorine is more electronegative than chlorine, and chlorine is more electronegative than hydrogen.
00:15 So if we have carbon surrounded by two fluorines and two hydrogens, then with fluorine being the most electronegative and the tetrahedral geometry not allowing for bond polarity cancellation, then the compound with fluorine and hydrogen would be the most polar, having a strong negative, partial negative on the fluorine side.
00:43 Then chlorine would be the next one with two chlorines and two hydrogens, having a partial negative on the chlorine side.
00:57 But if we have two chlorines and two fluorines, they actually end up partially canceling each other, so, although the fluorine side is partially negative, it's not as partially negative as chlorine by itself or fluorine by itself and just hydrogens...
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