Question

Which of the following options ranks the groups in order of decreasing priority according to the Cahn-Ingold-Prelog system, starting with the highest priority group first? Select the single best answer. $ONH_2 > NHCH_3 > CH_2NHCH_3$ $ONH_2 > NHCH_3 > CH_2NH_2$ $ONHCH_3 > NH_2 > CH_2NH_2$ $ONH_2 > NHCH_3 > CH_2NH_2$ $ONHCH_3 > NH_2 > CH_2NHCH_3$

Name: which of the following options ranks the groups in order of decreasing priority according to the cahn ingold prelog system starting with the highest priority group first select the single be 19458
Uploaded: 2024-10-12T22:27:46-08:00
Duration: 1 min 50 s
Channel: Ronald Prasad
Description: which of the following options ranks the groups in order of decreasing priority according to the cahn ingold prelog system starting with the highest priority group first select the single be 19458

          Which of the following options ranks the groups in order of decreasing priority according to the Cahn-Ingold-Prelog system, starting with the highest priority group first? Select the single best answer.

$ONH_2 > NHCH_3 > CH_2NHCH_3$
$ONH_2 > NHCH_3 > CH_2NH_2$
$ONHCH_3 > NH_2 > CH_2NH_2$
$ONH_2 > NHCH_3 > CH_2NH_2$
$ONHCH_3 > NH_2 > CH_2NHCH_3$

which of the following options ranks the groups in order of decreasing priority according to the cahn ingold prelog system starting with the highest priority group first select the single be 19458

Added by Soledad P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ronald Prasad

10/12/2024

Step 1

The CIP rules are used to assign R/S configurations to stereocenters and E/Z configurations to double bonds. The priority of a group is determined by the atomic number of the atoms directly attached to the stereocenter or double bond. If there is a tie, we move to Show more…

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Which of the following options ranks the groups in order of decreasing priority according to the Cahn-Ingold-Prelog system, starting with the highest priority group first? Select the single best answer. $ONH_2 > NHCH_3 > CH_2NHCH_3$ $ONH_2 > NHCH_3 > CH_2NH_2$ $ONHCH_3 > NH_2 > CH_2NH_2$ $ONH_2 > NHCH_3 > CH_2NH_2$ $ONHCH_3 > NH_2 > CH_2NHCH_3$