00:01
So for problem 38, we have to find the sign of a delta s for each of these reactions based on the information provided.
00:08
So first, we're going to look at how many moles are on both sides of the reaction.
00:12
So for a, we have three moles on the reactant side, but two moles on the product side.
00:19
And that means the number of particles is going to decrease in this reaction, which means entropy is also going to decrease, and thus the sign for delta s for part a is going to be negative since the products have an overall less entropy than the reactants.
00:40
For b, we have four moles on the reactants and four moles on the products.
00:46
So now we look at the states.
00:49
So for the reactants, we have four moles that are liquids.
00:55
But for the products, we have three moles that are liquids and one mole that is a gas.
01:00
So we start up with all liquid, but we end up with a gas.
01:05
So there's going to be an increase in overall entropy, and thus the sign for a delta s for part b is going to be positive...