Which of the following reactions or series of reactions would reduce 3-methylbutan-2-ol into 3-methylbutane? 1. NaOCH$_3$ 2. H$_2$SO$_4$/heat 2. pyridinium chlorochromate 2. ZnCl$_2$/HCl 3. ZnCl$_2$/HCl 2. t-butoxide/t-butanol 4. TsCl/pyridine 2. LiAlH$_4$
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The starting material is 3-methylbutan-2-ol, which is a secondary alcohol. The product is 3-methylbutane, which is an alkane. The transformation involves the reduction of an alcohol to an alkane. This means removing the -OH group and replacing it with -H. Show more…
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Which of the following reactions or series of reactions would reduce 3-methylbutan-2-ol into 2-methylbutane? A) 1. TsCl/pyridine and then 2. conc. KMnO4 B) 1. NaOCH3 and then 2. H2SO4/heat C) 1. pyridinium chlorochromate and then 2. ZnCl2/HCl D) 1. ZnCl2/HCl and then 2. t-butoxide/t-butanol E) 1. TsCl/pyridine and then 2. LiAlH4
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Which of the following reactions will yield propan-2-ol? 1 $\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3}+\mathrm{H}_{2} \mathrm{O} \quad \stackrel{\mathrm{H}^{+}}{\longrightarrow}$ $2 \quad \mathrm{CH}_{3}-\mathrm{CHO} \frac{(1) \mathrm{CH}_{3} \mathrm{MgI}}{(2) \mathrm{H}_{2} \mathrm{O}}$ $3 \mathrm{CH}_{2} \mathrm{O} \frac{(1) \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Mgl}}{(2) \mathrm{H}_{2} \mathrm{O}}$ $4 \mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3} \stackrel{\text { Neutral } \mathrm{KMnO}_{4}}{\longrightarrow}$ (a) 1 and 2 (b) 2 and 3 (c) 3 and 1 (d) 2 and 4
Which of the following reactions will yield 2-propanol? (1) $\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3}+\mathrm{H}_{2} \mathrm{O} \stackrel{\mathrm{H}^{\prime}}{\longrightarrow}$ (2) $\mathrm{CH}_{3} \mathrm{CHO} \stackrel{\text { (i) } \mathrm{CH}_{3} \mathrm{MgI}, \text { (ii) } \mathrm{H}_{2} \mathrm{O}}{\longrightarrow}$ (3) $\mathrm{CH}_{2} \mathrm{O} \quad$ (i) $\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{Mgl}$, (ii) $\mathrm{H}_{2} \mathrm{O}$ (4) $\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3} \stackrel{\text { Neutral } \mathrm{KMnO}_{4}}{\longrightarrow}$ (a) 1 and 3 (b) 2 and 4 (c) 1 and 2 (d) 3 and 4
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