00:01
So in this question we need to calculate the molarity of the solution when water is added to prepare each of the following.
00:09
So we have a, 25 .0 ml of 80 .0 molar concentration of acl solution is diluted to 500 ml.
00:17
So our first part of the question, our initial concentration c1 of acl was given as 18 molar, our v1 was given as 25 ml and then our v2 was given as 500 ml.
00:37
So we know that c1 v1 is equal to c2 v2.
00:42
So our final concentration c2 will be equal to our c1 v1 divided by our v2.
00:48
So our c2 will be equal to our c1 which is 18 times our v1 which is 25 divided by our v2 which is 500.
01:02
So our c2 will be equal to 0 .9 molar.
01:11
Thank you.
01:12
And then the b part of the question, it says that 50 .0 ml of 1 .50 molar concentration of acl solution is diluted to 125 ml.
01:30
So our c1 is given as 1 .5 molar and then our v1 was given as 50 ml and our v2 was given as 125 ml.
01:50
So therefore we can see that c1 v1 will be equal to c2 v2...