00:01
In this question, we need to pick a transition which is representing the emission of longest wavelength photo.
00:18
The options given are a, n equal to 3 to n equal to 1, b, n equal to 4 to n equal to 2, c, n equal to 3 to n equal to 4, d, d, n equal to 4, d, to 5 to n equal to 4 and e n equal to 1 to n equal to 2.
00:45
For finding the wavelength of different transitions, the formula used is 1 by lambda is equal to 1097371 1 by n1 square minus 1 by n2 square.
01:03
We can consider each transitions, that is, for a, 1 by lambda is equal to 109737, 1 by n1 square is equal to 1 square minus 1 by 3 square.
01:27
That is obtained as lambda is equal to 1 .0252 into 10 raise to minus 5 centimeter inverse.
01:36
Now for b, 1 by lambda 1 .10 is equal to 109737, 1 by 2 square minus 1 by 4 square...