00:01
Hello students, in this question we have been given some functions and we have to tell if those functions are eigenfunctions or not.
00:07
So let me tell you what an eigenfunction is.
00:09
Suppose we have a function represented by fx and we are applying an operator a cap on it.
00:15
Now if this operation gives back the same function multiplied with a constant value then this fx is known as an eigenfunction of this operator.
00:25
So this a is known as the eigenvalue of this function.
00:32
So our first function is a e raised to the power minus 3x plus b e raised to the power minus 3 iota x.
00:41
So this is the function and let's check it.
00:43
So we will apply the operator that is given.
00:46
So operator that is given to us is differential operator d by dx.
00:50
So this is what we will apply on this function.
00:54
So let's differentiate it.
00:56
So a will be constant derivative of e raised to the power minus 3x will be same and derivative of minus 3x will be equal to minus 3.
01:04
Now let's do the derivative of our second term.
01:07
B will be constant derivative of e raised to the power minus 3 iota x will be e raised to the power minus 3 iota x and now differentiation of this power will be equal to minus 3 iota.
01:19
Now we can take minus 3 common from here and we will finally get a e raised to the power minus 3x plus b iota.
01:31
So this iota will stay here e raised to the power minus 3 iota x.
01:35
Now this is the function that we have got and this is the constant value.
01:43
Now if we look at our initial functions this so these both functions are actually not the same because of this iota value.
01:52
So for being called as a eigenfunction both functions must be same.
01:57
So that is why the function given in option a is not an eigenfunction.
02:06
The second function that is given to us is sin square x.
02:09
So let's just differentiate it and sin square x can be written as 1 minus cos 2x divided by 2.
02:24
If you are wondering where this equation has come from we can calculate it by the formula of cos 2x.
02:32
So cos 2x is sin square x minus sin square x plus cos square x.
02:40
Now this cos square x can be replaced by 1 minus sin square x.
02:50
So cos 2x will be equal to 1 minus 2 sin square x.
02:56
We can rearrange this formula into this to calculate the value of our sin square x.
03:01
So sin square x will be 1 minus cos 2x divided by 2.
03:05
Now let's differentiate this function.
03:10
So this will be equal to d by dx of 1 by 2 minus d by dx of 1 by 2 cos 2x.
03:23
So derivative of constant will be 0 minus 1 by 2 will be taken out common.
03:30
Derivative of cos 2x is minus sin 2x and derivative of 2x is 2...