00:01
Okay, so we have to find out the odd one out compound here based on c 13 nmr spectra.
00:11
So we have to check basically the signals, okay, in the given structures.
00:17
And the signals, so they are the carbon atoms which have equivalent environment.
00:25
So they will show the same kind of signal.
00:27
Okay so now first of all we have the one so we have a structure like this okay now see here this carbon atom this carbon atom is attached to a chloro group and then to this alkyl group right so this is the first signal we have then this carbon atom is attached to two chloro groups and then we have two alkyl groups and then this is the first signal we have then this this carbon atom is attached to no chloro group attached here, only hydrogen atoms are attached, and then it has alkyl group containing chloro groups.
01:17
Okay.
01:18
So this will show second signal and this will show third signal.
01:23
So in this way we have three signals here in this structures because all the three carbon atoms have different environment, b part.
01:35
So we have chloro group, chloro group, chloro group.
01:46
So now this carbon atom has two chloro group and this alkali group.
01:56
This carbon atom has one chloro group and rest is alkyl group...