00:01
Before answering these questions about i .o .f3, we need to draw the lewis structure.
00:08
Iodine has seven valence electrons.
00:11
Oxygen has six.
00:12
Floreen has seven.
00:14
There are three of them.
00:15
So we have a total of 34 valence electrons.
00:18
Iodine is actually in the middle, despite the fact that it shows oxygen in the middle.
00:24
Because for this particular species, we're going to have to have an expanded octet, and oxygen could not have an expanded octet.
00:31
Iodine needs to be in the middle.
00:34
When we bond all four of the atoms to iodine and we achieve an octet for all the peripheral atoms, we will have used 32 valence electrons, but we have 34, so we need to put a lone pair on iodine.
00:50
If oxygen were in the middle, we couldn't do this.
00:52
We couldn't have an expanded octet.
00:55
And in order to achieve all zero formal charges, we can double bond this oxygen to the iodine and and expand the octet even more.
01:09
Now all the formal charges are zero.
01:15
So let's answer the questions.
01:17
Which are the following statements about ios 3 is false? the electron pair geometry is trigonal bipramidal.
01:27
So we have one, two, three, four, five, five electron groups...