00:01
Hello, i am your teacher for this question and our question says that for each ordered pair determine whether it is a solution to the system of equations.
00:09
The equation first is given as 12x minus 2y equals to minus 10 and y is supposed to 6x plus 5.
00:15
So first equation is given as 12x minus of 2y is equal to minus of 10 and the second equation is given as y is equal to 6x plus 5.
00:29
All right.
00:31
So this is the first is the first of 2y is equal to 6x plus 5.
00:31
First equation, this is the second equation using second we will be writing that 12x using second in the first equation you will be writing 12 x minus of 2 times of 6x plus 5 is equal to minus 10.
00:48
So you will be seeing this as that 12 x minus of 12 x minus 10 is equal to minus of 10.
00:54
So 12 x to 12 x get cancelled you will be writing minus 10 equals to minus 10.
00:58
You will be saying that this is a satisfactory equation.
01:00
All right now just see that this is nothing but that both equations are same in the simplified form this will also be written as y equals to 6x plus 5 that's why we are getting minus 10 equals to 10 so what i'll be telling you is that is you will be writing y equals to 6x plus 5 now you will be seeing that points that are 2 comma minus 3 first point is 2 comma minus 3 so we will be checking that that is satisfying or not so 6 times 2 plus 5 you will be seeing that 17 is not going to be equal to minus 3.
01:31
Alright.
01:32
So you will be writing that 2.
01:33
Minus 3 is not a solution.
01:35
Then and after 0 .5, we will be checking 0 .5...