Which statement a d is not correct if all are correct...

Which statement, A-D, is not correct? If all are correct, respond E. Pure water at 25°C has A. $K_w = 1.0 \times 10^{-14}$ B. pH = 7 C. pOH = 7 D. $[H_3O^+] = [OH^-]$ E. A-D are all correct

Transcript

00:01 So for 11 our options should be right e and that is what a to d all are correct.

00:12 All are correct.

00:16 Is that clear? so as we know, the reaction temperature as we know of 25 degrees celsius, that means 298 k .m.

00:30 So as we know, h22 plus h2 then we will get h3 plus okay plus we can write oh so what we can write as we know ph will be equal to minus law and here concentration h plus and ph will be equal to actually sorry not ph actually okay so this will be what p -o -h will be equal to what we can write minus lock and this will be what? concentration oh is that clear? so when we talk about this, so what we can write? we can write like this.

01:32 K -e -q will be equal to concentration h3 plus, right.

01:40 Right okay and here oh h minus concentration then over we can write concentration h2o and here concentration h2o is that clear right what is pure liquid and therefore its concentration remain constant therefore constant of water is negligible so now what we can we can write like this k w will be equal to concentration h3 o plus and concentration o h minus exactly experimentally it has been found that concentration of h plus at 298 kibule is 10 to the power minus 7 molarity so we can write because h plus concentration equal to oh h minus therefore we can write k w will be equal to 10 to the power minus 7 concentration okay and here we can also we can write okay 10 to the power minus 7 concentration so that means this will be equal to 10 to the power minus 40 equal to k w right so what we can write now because we know k w is sq concentration and oh h minus concentration so we will take both side log so what we can write law k w will be equal to log concentration h3 o plus okay and plus we can write log concentration oh h minus is that clear so what we can write log here 10 to the power minus 14 will be equal to log concentration h3 plus plus lock here will be actually oh is that clear so now we can write log 10 to the power minus 40 equal to lock concentration 10 to the power minus 7 okay plus lock concentration 10 to the power minus 7 right both sides we will multiply with minus 1 then we will get okay so now we will get here minus law 10 to 0 .10 equal to what we can write minus law concentration 10 to 4 minus 7 concentration and this is nothing but here and here what we can write plus and minus log okay 10 to the power minus 7 then it will be actually nothing but p -o -h is that here so what we can write 14 is equal to 7 plus 7 is that here so 14 equal to what we can write p h plus p o h right is that clear so this will be answered for 11th okay so further what we can write so further for 12th we can write for 12th hour option a should be right which will be partially neutralized of weak aced with the strong base so now we will talk about 13th so for 13th ph will be equal to just respect.

05:55 P .h will be equal to here concentration 3...

Question

Which statement, A-D, is not correct? If all are correct, respond E. Pure water at 25°C has A. $K_w = 1.0 \times 10^{-14}$ B. pH = 7 C. pOH = 7 D. $[H_3O^+] = [OH^-]$ E. A-D are all correct

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