00:01
To draw the lewis structure for no2 minus, this being the nitrite anion, we need to calculate the number of valence electrons.
00:13
Nitrogen has five, oxygen has six, and there are two of them, plus one more because of the negative charge.
00:23
So this gives us 18 total valence electrons.
00:27
So if nitrogen is in the middle, we can put the oxygens on each side.
00:33
This used up, each bond being two electrons, four electrons.
00:36
Electrons, so we have a total of 14 left over.
00:43
If we attempt to give each oxygen an octet, two, four, or let's see one, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve.
00:56
We've used up twelve more, so we have two left...