Which table correctly displays the information provided within the problem below? A space shuttle is flying north at 6,510 m/s. It accelerates at 28.4 m/s² directly northeast. After 60.0 s, what is the direction of the velocity of the plane? A) | | x | Y | | :--- | :--- | :--- | | Vi | 0 | 6510 | | Vf | ? | ? | | a | 20.1 | 20.1 | | ?x | | | | t | 60.0 | 60.0 | B) | | x | Y | | :--- | :--- | :--- | | Vi | 6510 | 0 | | Vf | ? | ? | | a | 28.4 | 28.4 | | ?x | | | | t | 60.0 | 60.0 | C) | | x | Y | | :--- | :--- | :--- | | Vi | ? | ? | | Vf | 996 | 6430 | | a | 28.4 | -9.80 | | ?x | | | | t | 60.0 | 60.0 |
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In terms of the coordinate system, this can be represented as 0 in the x-direction (east-west) and 6510 in the y-direction (north-south). The acceleration of the space shuttle is given as 28.4 m/s² in the northeast direction. This means the acceleration is split Show more…
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