Question

Which two of the following equations are quadratic, or can be rearranged into a quadratic equation? Select one or more: \frac{1}{3t+2} = \frac{3t}{t+2} 3q^2 + 2q = 0 \frac{x^2}{3x+2} = \frac{1}{2x} 3x + 2 = 2x + 3 3z + 2 = 0

          Which two of the following equations are quadratic, or can be rearranged into a quadratic equation?
Select one or more:
\frac{1}{3t+2} = \frac{3t}{t+2}
3q^2 + 2q = 0
\frac{x^2}{3x+2} = \frac{1}{2x}
3x + 2 = 2x + 3
3z + 2 = 0

Which two of the following equations are quadratic, or can be rearranged into a quadratic equation?
Select one or more:
(1)/(3t+2) = (3t)/(t+2)
3q^2 + 2q = 0
(x^2)/(3x+2) = (1)/(2x)
3x + 2 = 2x + 3
3z + 2 = 0

Added by Joel C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Breanna Ollech

09/20/2023

Step 1

Step 1: A quadratic equation is an equation of the form $ax^2 + bx + c = 0$, where $a$, $b$, and $c$ are constants and $a$ is not equal to 0. Show more…

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Which two of the following equations are quadratic, or can be rearranged into a quadratic equation? Select one or more: $\frac{1}{3t+2} = \frac{3t}{t+2}$ $3q^2 + 2q = 0$ $\frac{x^2}{3x+2} = \frac{1}{2x}$ $3x+2=2x+3$ $3z+2=0$