00:01
For this problem, we consider the equation of the first line, line 1, to be y equals 2x plus 8.
00:10
We want to find the equation of the line that's perpendicular to line 1, passing through negative 3, negative 8.
00:18
Now, the first thing we need to do is to find the slope of line 1.
00:24
And to find the slope, we have to use y equals mx plus b, where m is the slope of the line.
00:36
Since l1 is defined as y equal to 2x plus 8, then the slope of line 1, let's call that m1, is equivalent to 2.
00:53
2.
00:54
Next, we want to find the slope of the line that we want to solve for.
01:01
So this line is perpendicular to line 1, then the slope of this line, let's call that m, is equivalent to negative 1 over the slope of line 1, or that's the negative reciprocal of the given line.
01:19
And because m sub 1 is equal to 2, then the slope of the line we want to find which is perpendicular to line 1 is negative 1 over.
01:31
And the next step will be to use the point slope formula to find the equation of the needed line.
01:39
The point slope formula is given by y minus y1 equal to m times x minus x1 where x1, y1 is the given point...