A 34,457 Mg ocean liner has an initial velocity of 5 km/h. Neglecting the frictional resistance of the water, determine the time in seconds required to bring the liner to rest by using a single tugboat which exerts a constant force of 155 kN. Use impulse-momentum. Round your answer to the nearest whole number. Use the proper conversion factors/units.
Added by Jasmine W.
Close
Step 1
1 Mg = 10^6 grams = 10^6 kg 1 kg = 9.8 N (acceleration due to gravity) Therefore, 1 Mg = 10^6 kg * 9.8 N/kg = 9.8 * 10^6 N Show more…
Show all steps
Your feedback will help us improve your experience
Sonu L and 87 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A truck is accelerated by a constant force of 4.7 kN. Its velocity increases from 38 km/hr to 56 km/hr in a time of 9.3 s. Calculate the mass of the truck in SI units.
Adi S.
A body of mass 5 kg starts from the origin with an initial velocity of u=(30i+40j)m/s. A constant force of F=(?i^?5j^?)N acts on the body. Find the time in which the y-component of the velocity becomes zero.
Kajal R.
In a new system of units, 1 unit of Force is 100N, 1 unit of velocity is 2 m/s and 1 unit of time is 4 sec. Then density of water 1000 kg/m^3 = _____ units in new system?
Sri K.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Watch the video solution with this free unlock.
EMAIL
PASSWORD