Why does the arc of length (π)/(6) on the unit circle correspond to the point ((√(3))/(2), (1)/(

Name: Why does the arc of length (π)/(6) on the unit circle correspond to the point ((√(3))/(2), (1)/(2)) on the unit circle?
Uploaded: 2023-11-07T01:39:55-08:00
Duration: 1 min 3 s
Channel: Kathleen Carty
Description: Why does the arc of length (π)/(6) on the unit circle correspond to the point ((√(3))/(2), (1)/(2)) on the unit circle?

So a squared plus b squared equals c squared and that is the Pythagorean theorem. We want to kno

Question

Why does the arc of length $\frac{\pi}{6}$ on the unit circle correspond to the point $(\frac{\sqrt{3}}{2}, \frac{1}{2})$ on the unit circle?

          Why does the arc of length $\frac{\pi}{6}$ on the unit circle correspond to the point $(\frac{\sqrt{3}}{2}, \frac{1}{2})$ on the unit circle?

Why does the arc of length (π)/(6) on the unit circle correspond to the point ((√(3))/(2), (1)/(2)) on the unit circle?

Added by Dennis C.

Precalculus with Limits

Ron Larson 2nd Edition

Thanks for your feedback!

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