Question

1. a. Why is calcium chloride (CaCl2) more effective at reducing the freezing point of water compared to sodium chloride on a molar basis. (hint use: molality(m)= moles of solute/ kg of solvent). b. Why is calcium chloride (CaCl2) less effective at reducing the freezing point of water compared to sodium chloride (NaCl) on a weight basis?

          1.
a. Why is calcium chloride (CaCl2) more effective at reducing the freezing point of water compared to sodium chloride on a molar basis.
(hint use: molality(m)= moles of solute/ kg of solvent).
b. Why is calcium chloride (CaCl2) less effective at reducing the freezing point of water compared to sodium chloride (NaCl) on a weight basis?

1.
a. Why is calcium chloride (CaCl2) more effective at reducing the freezing point of water compared to sodium chloride on a molar basis.
(hint use: molality(m)= moles of solute/ kg of solvent).
b. Why is calcium chloride (CaCl2) less effective at reducing the freezing point of water compared to sodium chloride (NaCl) on a weight basis?

Added by Albert B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Madhur L

03/23/2023

Step 1

When dissolved in water, both calcium chloride (CaCl$_2$) and sodium chloride (NaCl) dissociate into their respective ions: CaCl$_2$ dissociates into one Ca$^{2+}$ ion and two Cl$^-$ ions, while NaCl dissociates into one Na$^+$ ion and one Cl$^-$ ion. Show more…

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Why is calcium chloride (CaCl2) more effective at reducing the freezing point of water compared to sodium chloride on a molar basis? (hint use: molality(m)= moles of solute/ kg of solvent). Why is calcium chloride (CaCl2) less effective at reducing the freezing point of water compared to sodium chloride (NaCl) on a weight basis?