In this case, $\hat{p} = \frac{34}{149}$, $z = 1.645$ for a 90% confidence interval, and $n = 149$.
$$CI = \frac{34}{149} \pm 1.645 \sqrt{\frac{\frac{34}{149}(1-\frac{34}{149})}{149}}$$
Calculating the confidence interval, we get:
$$CI = 0.228 \pm 0.064$$
So,
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