00:01
Hi there.
00:02
We are given the mass of one of the reactants in this problem, and we are asked to calculate the mass of one of the products.
00:10
So this is going to be a mass -to -mass stochometry problem.
00:18
And anytime we have a stoichiometry problem, we know we need a balanced equation.
00:23
So the first thing i want to do is write a balanced equation.
00:26
So we are starting with the ethanol, which i am going to write its formula for it.
00:32
It's molecular formula.
00:37
So c2h5oh.
00:40
That is the same thing as is given there.
00:42
It's just written more in its condensed molecular form.
00:46
That reacts with oxygen.
00:50
And we're told that it produces water and vinegar, or in other words, acetic acid, which is ch3, c -o -o -h.
01:06
Okay.
01:07
When we look at this, we need make sure it's balanced, first of all.
01:09
So there are two carbons on each side.
01:12
Those are balanced.
01:13
On the reactant side, six hydrogen on the product side, and three oxygen on each side.
01:20
So this is balanced as is.
01:21
Everything is in a one -to -one -to -one mole ratio.
01:25
We are told that we have 4 .67 grams of the ethanol, and we're trying to figure out how many grams of acetic acid will be formed.
01:37
So again, this is a mass -to -mass problem.
01:39
So the first step, we need the molar mass to convert from grams to moles.
01:45
So calculating the molar mass of c -tacet, and so calculating the molar mass of 2h5 -oh -h by adding together two carbons, six hydrogens, and one oxygen, adding those masses together, we get 46 .07 grams per mole is the molar mass.
02:02
All right, so that will get us to moles of the ethanol.
02:06
Then we can use the mole ratio to get to moles of acetic acid, and then use acetic acid's molar mass to convert back to grams.
02:15
And acetic acid acid's molar mass is 60 .3 .3 .5 .5...