With the aid of a string, a gyroscope is accelerated from rest to 32 rad/s in 0.40 s under a constant angular acceleration. (a) What is its angular acceleration in rad/s2 ? (b) How many revolutions does it go through in the process?
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Step 1
40 s. Plugging in the values, we get: α = (32 rad/s - 0 rad/s) / 0.40 s α = 32 rad/s / 0.40 s α = 80 rad/s^2 Show more…
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With the aid of a string, a gyroscope is accelerated from rest to $32 \mathrm{rad} / \mathrm{s}$ in $0.40 \mathrm{s}$ under a constant angular acceleration. (a) What is its angular acceleration in $\operatorname{rad} / \mathrm{s}^{2}$ ? (b) How many revolutions does it go through in the process?
With the aid of a string, a gyroscope is accelerated from rest to 32 rad/s in 0.40 s. What is its angular acceleration in rad/s^2? How many revolutions does it go through in the process?
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