Question

With vacuum between its plates, a parallel-plate capacitor has capacitance 4.50 μF. You attach a power supply to the capacitor, charging it to 2.40 kV, and then disconnect it. You then insert a dielectric sheet that fills the space between the plates. The potential difference between the plates decreases to 1.10 kV, and the charge on each plate remains constant. Find the energy stored in the capacitor before you insert the sheet. U = Find the energy stored in the capacitor after you insert the sheet. U =

Name: with vacuum between its plates a parallel plate capacitor has capacitance 450 f you attach a power supply to the capacitor charging it to 240 kv and then disconnect it you then insert a diel 29389
Uploaded: 2022-09-17T14:33:35-08:00
Duration: 3 min 19 s
Channel: Vishal Gupta
Description: with vacuum between its plates a parallel plate capacitor has capacitance 450 f you attach a power supply to the capacitor charging it to 240 kv and then disconnect it you then insert a diel 29389

          With vacuum between its plates, a parallel-plate capacitor has
capacitance 4.50 μF. You attach a power supply to
the capacitor, charging it to 2.40 kV, and then
disconnect it. You then insert a dielectric sheet that fills the
space between the plates. The potential difference between the
plates decreases to 1.10 kV, and the charge on each
plate remains constant. Find the energy stored in the capacitor
before you insert the sheet.
U = 
Find the energy stored in the capacitor after you insert the
sheet.
U =

Added by Jillian M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

09/17/2022

Step 1

The formula for the energy stored in a capacitor is U = 1/2 * C * V^2, where C is the capacitance and V is the voltage. So, U = 1/2 * 4.50 μF * (2.40 kV)^2 = 12.96 Joules. Show more…

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With vacuum between its plates, a parallel-plate capacitor has capacitance 4.50 μF. You attach a power supply to the capacitor, charging it to 2.40 kV, and then disconnect it. You then insert a dielectric sheet that fills the space between the plates. The potential difference between the plates decreases to 1.10 kV, and the charge on each plate remains constant. Find the energy stored in the capacitor before you insert the sheet. U = Find the energy stored in the capacitor after you insert the sheet. U =