Worksheet: Limiting Reactants Name 1. 4 FeCl3 + 3 O2 -> 2...

Worksheet: Limiting Reactants Name______ 1. 4 FeCl3 + 3 O2 -> 2 Fe2O3 + 6 Cl2 a. How many moles of chlorine gas can be produced if 4 moles of FeCl3 react with 4 moles of O2? SHOW ALL WORK! b. What is the limiting reactant? c. What is the excess reactant? 2. Use the following BALANCED equation. 2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O a. If 15 g of C2H6 react with 45 g of O2, how many grams of water will be produced? b. What is the limiting reactant? c. What is the excess reactant?

Transcript

00:01 Hello, so here the question is based on limiting reagent.

00:05 Okay, so first of all let us understand what is a limiting reagent.

00:09 Okay, so limiting reagent is those substance that is present in a reactant side.

00:15 Okay, or those substance that is reacting to give the exact amount of product.

00:30 Okay, or otherwise we can say limiting reagent determines the amount of product formed.

00:42 Okay, amount of product formed.

00:47 So here in this question we are provided with an equation that is 4 fecl3 plus 3 o2 giving 2 fe2o3 plus 6 cl2.

01:01 Okay, so here in this question we are provided with 4 moles of oxygen.

01:06 Okay, and we need to find out how many moles of chlorine will be produced.

01:13 Okay, so when you take a look into the equation that is given, 4 moles of fecl3 is reacting with 3 moles of oxygen to give 6 moles of chlorine.

01:26 Okay, now in the question what do we have? we have 4 moles of oxygen.

01:30 The number of moles of fecl3 remains the same.

01:34 Okay, which means we require only 3 moles but 1 mole is in excess.

01:42 Okay, but considering the reaction we can see that oxygen is the limiting reagent here.

01:51 Okay, so the number of moles of oxygen will determine the number of moles of chlorine that is produced over here.

01:59 Okay, so what can we say? one mole will be in excess and the number of moles of chlorine that will be produced will be 6 moles itself because we require only 3 moles but we have 4 moles and 1 mole is in excess.

02:15 Okay, so when 4 moles will react with 3 moles to give you 6 moles of chlorine.

02:20 Now for the second part of the question we are given with the equation 2 c2h6 plus 7 o2 giving 4 co2 plus 6 h2o.

02:33 Okay, now here we need to find the limiting reagent, the excess reagent and also the mass of water produced when we have the mass of c2h6 is given as 15 gram and the mass of oxygen is given as 45 grams.

03:01 Okay, so let's see the answer here...

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