00:01
Hi, i'm david and i'm here to have you answer your question.
00:04
Now let me bring up your question here.
00:07
In this question here, contamination problems in semi -conductor manufacturing can result in three times.
00:16
The fact is the functional default.
00:19
The function will be the minor and there will be no defects.
00:23
Now we have the probability 20 and 30 for the contamination problem result in the functional so probability for the functional defect equal to the 0 .2, probability for the minor defect equals to 0 .3 and probability that no defect, it will equal to 1 minus 0 .2, minus 0 .3, equal to 0 .5.
00:54
Now assume then the defect on the 10, so n not equal to 10.
00:59
And in the part i ask us to find the proper purpose.
01:03
That the 10 contamination problem results in two functional defect and 5 minor effect probability under 2 functional and then 5 minor so the rest it will be we have the 3 that will be no defect now this one on the multidomial distribution we have the total could be the n which is the formula will be n choose n1 n2, n3, then we will be b1, b2 bound 2, b3 bound 2, b3 bound and 3, that will be the formula.
01:45
Now we have the n equal to the 10.
01:47
N1 equal to this will be 2, and then n2 equal to 5, and n3 equal to 3...