00:01
Hi, in this question it is given that there is a wrecking ball whose weight is 5 ,330 newtons.
00:12
This wrecking ball is supported by a boom and cable.
00:18
This is the supporting cable and this is the boom of the grain.
00:24
And the weight of the boom is also given.
00:28
Weight of the boom let us say small w is equal to small m g which is given as 2 ,990 newtons now we need to determine the tension in the supporting cable also we need to find the magnitude of the force exerted on the lower end of the boom at the hinge p let's consider the triangle bpc and this is 90 degrees and this one is 48 degree therefore 1a t minus 90 minus 48 we obtained 42 degrees the angle p c b will be equal to 42 degrees similarly here also now let us consider the triangle a b c this triangle this angle how much included angle that is to be determined so this is 32 degree and this is 90 degree so so we can find that the angle a, c, b will be equal to 58 degrees.
01:38
This is 42 degree, 58 minus 40 to 16 degrees.
01:42
This one is 16 degrees.
01:44
Now to determine the tension in the supporting cable, we need to take the moment about the point peak.
01:51
Both this particular point, let us take the moment.
01:54
And the length is l.
01:57
The length of the boom we can consider it as capital l.
02:03
Now, the algebraic summation of all the moments acting on the system must be zero.
02:10
That is the equilibrium condition.
02:15
Now, we can write t, that is, this is the tension t, which is acting on the supporting cable.
02:25
Since this is inclined to x axis and y axis will have two components.
02:29
One will be the horizontal component.
02:30
Another will be the vertical component.
02:34
T multiply with the perpendicular distance.
02:39
Perpondical distance will be l sine 58 degrees.
02:46
Or we can say that 90 minus 32 degrees minus small m .g, this one, this weight, weight of the boom.
03:02
That is small w multiply with l...