00:01
In this problem, we are given the wave equation y equals 0 .02, sine 30 t minus 4x.
00:09
Here, x and y, they are in meters.
00:14
And the variable t, which represents time, this is in seconds.
00:19
And we are required to determine, first, the amplitude of this wave, then we are required to determine the frequency of this wave, and then we are required to determine the speed and the wavelength.
00:37
So let's take the speed as v and the wavelength as lambda.
00:41
So here we just compared this wave equation with the standard form, that's y equals a sine omega t minus kx.
00:50
And on comparison, we see that the amplitude represented by a, that is 0 .02.
00:57
So we got the amplitude as 0 .0 .2.
01:00
02 meters, which is 2 centimeters.
01:04
And we further observe that omega is 30 on comparison...