00:01
In this problem, we're given that a variable q varies directly as m and the square of n.
00:13
So n squared, and it varies inversely as p.
00:21
Now, that means that the product of qp divided by m times n squared is equal to a constant.
00:34
So that means that for any values, what's called in q sub 1, p sub 1, divided by m sub 1, n sub 1 squared, that is equal to another value q sub 2 times b sub 2 divided by m sub 2 times n sub 2 squared.
00:58
Now we have to find out q when m is equal to 4, n equals 18, and p equals 2 given that m equals 3, n equals 6, and p equals 12.
01:11
So let's make the substitution.
01:14
So when q is equal to 2, we're given that p is equal to 12, and we're given that m is equal to 3, and n is equal to 6.
01:29
So that's 6 squared...