00:01
Hi, in this question we are given by equation and we have to find the reduction and oxidation half reaction of the given equation.
00:09
So the reduction half reaction will be h3 aso4 is converting into ash3 because the reduction take place for h3 aso4 into ash3 and the oxidation number of arsenic in h3 aso4 is plus 5 and the oxidation number of arsenic in ash3 is minus 3.
00:41
So the reduction will take place and there is 8 electron add to the h3 aso4 after the reduction.
00:53
So now we have the oxidation half reaction and i minus is converting into i2 after the oxidation.
01:04
The oxidation number of i minus is minus 1 and for i 2 the oxidation number is 0.
01:10
So there is the change of one electron.
01:13
So one electron is loss in the oxidation reaction.
01:20
So now we have to balance the reduction and oxidation half reactions.
01:26
So firstly we have one arsenic on the left side and one arsenic on the product side.
01:33
So arsenic is already balanced.
01:36
Now we have 4 oxygen on the left side of the reaction and we have no oxygen on the right side of the reaction...