Question

U1A LM358 R4 1k R1 1k R2 1k R3 1k SIM1 LCD1 1602

          U1A
LM358
R4
1k
R1
1k
R2
1k
R3
1k
SIM1
LCD1
1602
        
U1A
LM358
R4
1k
R1
1k
R2
1k
R3
1k
SIM1
LCD1
1602

Added by Steven E.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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write me a code for this circuit LC01 U1A 8868 SIMT 8 LINO R2
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Transcript

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00:01 So we have in the problem an operational amplifier or an up -amp with saturation voltages of 15 for the positive and negative saturations, and we are to solve for the output voltage given the inputs on the left.
00:22 So this is what we call an open loop up -am, which means that there is no feedback mechanism.
00:33 In the diagram.
00:36 So for open -loop up -amps, the v -out is equal to the gain times the difference in the voltages across the non -inverting and inverting terminals, where the gain is taken to be infinite or very, very large.
00:57 So here, the v plus or the non -inverting voltage should be equal to 12 times 10 kilo -ooms divided by 2 kilo -ooms plus 10 kilo -ooms.
01:18 So what we did here is we used voltage division for these series of resistors here.
01:27 So this will give us a non -inverting input of 10 volts.
01:36 For the inverting input, it is connected to a power supply of 5 volts.
01:41 So we have b minus being equal to 5 volts.
01:47 So substituting this into our equation for the output voltage, we have infinity times 10 minus 5, which is equal to positive infinity.
02:03 So in this up -amp, we have a maximum positive value of 15 dictated by your v plus here...
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